What enables the moon to continue to orbit around the earth?
Q. A satellite will only orbit the earth for a few years before it will be forced out of orbit but the moon has been orbiting for 15 billion years, so what prevents the earths gravity from pulling it in? What keeps it going and why doesnt the friction caused by the earths gravity(the force that prevents it from flying away) slow it down?
Asked by ByeBuyamericanPi - Wed Aug 16 22:08:19 2006 - - 14 Answers - 3 Comments
A. It's the calming affect of cheese.
Answered by ceprn - Wed Aug 16 22:15:24 2006
Q. A satellite will only orbit the earth for a few years before it will be forced out of orbit but the moon has been orbiting for 15 billion years, so what prevents the earths gravity from pulling it in? What keeps it going and why doesnt the friction caused by the earths gravity(the force that prevents it from flying away) slow it down?
Asked by ByeBuyamericanPi - Wed Aug 16 22:08:19 2006 - - 14 Answers - 3 Comments
A. It's the calming affect of cheese.
Answered by ceprn - Wed Aug 16 22:15:24 2006
What is the period of the asteroids orbit & orbital velocity?
Q. The period of the earth around the sun is 1 year and its distance is 150 million km from the sun. An asteroid in a circular orbit around the sun is at a distance 393 million km from the sun. A. What is the period of the asteroid s orbit? Answer in years. B. What is the orbital velocity of the asteroid? Assume there are 365 days in one year.
Asked by mel - Mon Jan 11 09:01:13 2010 - - 1 Answers - 0 Comments
A. The question uses GmM/R^2 = mV^2/R The gravitational force = the centripetal force. The information about the earth determines the mass of the Sun (M) in the above formula. m cancels out in both cases. You know G, R which must be converted to meters. T which must be converted to seconds (365*24*3600) V which also must be converted to meters (2*pi*R)/T Solve for M. You should get about 2*10^30 I think. Now start again. Do the same thing for the satellite. The m's cancel You know R (convert to meters) You know the circular orbit (from 2*pi*R) you know G you know the mass of the Sun (M) You will solve for V which will give you T when you use d=2*pi*R. The formula for V = d/t
Answered by jcherry_99 - Mon Jan 11 09:32:22 2010
Q. The period of the earth around the sun is 1 year and its distance is 150 million km from the sun. An asteroid in a circular orbit around the sun is at a distance 393 million km from the sun. A. What is the period of the asteroid s orbit? Answer in years. B. What is the orbital velocity of the asteroid? Assume there are 365 days in one year.
Asked by mel - Mon Jan 11 09:01:13 2010 - - 1 Answers - 0 Comments
A. The question uses GmM/R^2 = mV^2/R The gravitational force = the centripetal force. The information about the earth determines the mass of the Sun (M) in the above formula. m cancels out in both cases. You know G, R which must be converted to meters. T which must be converted to seconds (365*24*3600) V which also must be converted to meters (2*pi*R)/T Solve for M. You should get about 2*10^30 I think. Now start again. Do the same thing for the satellite. The m's cancel You know R (convert to meters) You know the circular orbit (from 2*pi*R) you know G you know the mass of the Sun (M) You will solve for V which will give you T when you use d=2*pi*R. The formula for V = d/t
Answered by jcherry_99 - Mon Jan 11 09:32:22 2010
How long does it take for Venus to make one orbit around the sun?
Q. The earth orbits the sun once per year at the distance of 1.50 x 10^11m. Venus orbits the sun at a distance of 1.08 x 10^11m. These distances are between the centers of the planets and the sun. How long (in earth days) does it take for Venus to make one orbit around the sun?
Asked by physik - Mon Oct 27 20:03:24 2008 - - 4 Answers - 0 Comments
A. VENUS Image of Venus Venus is the second closest planet to our Sun at an average distance 67 million miles. It revolves around the Sun every 225 Earth days, but its rotation takes 243 Earth days. One other interesting note is that Venus rotates clockwise, the only planet in our solar system to do so, and contrary to its own orbit around the Sun. Research suggests that the "backward" rotation is caused by tides which are raised in the thick atmosphere by the Sun, and with friction interaction between the atmosphere and planet itself. It is hypothesized that these interactions caused Venus's rotation to slow, stop, and then reverse. This is somewhat similar to what is happening here on Earth, as our Moon's pull on our oceans causes… [cont.]
Answered by Mittmoudh R - Mon Oct 27 20:07:19 2008
Q. The earth orbits the sun once per year at the distance of 1.50 x 10^11m. Venus orbits the sun at a distance of 1.08 x 10^11m. These distances are between the centers of the planets and the sun. How long (in earth days) does it take for Venus to make one orbit around the sun?
Asked by physik - Mon Oct 27 20:03:24 2008 - - 4 Answers - 0 Comments
A. VENUS Image of Venus Venus is the second closest planet to our Sun at an average distance 67 million miles. It revolves around the Sun every 225 Earth days, but its rotation takes 243 Earth days. One other interesting note is that Venus rotates clockwise, the only planet in our solar system to do so, and contrary to its own orbit around the Sun. Research suggests that the "backward" rotation is caused by tides which are raised in the thick atmosphere by the Sun, and with friction interaction between the atmosphere and planet itself. It is hypothesized that these interactions caused Venus's rotation to slow, stop, and then reverse. This is somewhat similar to what is happening here on Earth, as our Moon's pull on our oceans causes… [cont.]
Answered by Mittmoudh R - Mon Oct 27 20:07:19 2008
What are some good places to look for Dark Orbit tips and Dark Orbit cheats?
Q. I've been playing this game call Dark Orbit and I was wondering what are some good sites to find tips and cheats on. There's a lot of misinfo out there and I don't want to pay for a scam. Just so some of you who have not play this game. It is a space battle game where you control your own space ships and you kill aliens and other players. It is a lot of fun. Hope to see you in the game.
Asked by Tina A - Thu Jul 2 12:20:58 2009 - - 1 Answers - 1 Comments
A. im looking for the same thing
Answered by Kyle - Fri Jul 3 19:53:12 2009
Q. I've been playing this game call Dark Orbit and I was wondering what are some good sites to find tips and cheats on. There's a lot of misinfo out there and I don't want to pay for a scam. Just so some of you who have not play this game. It is a space battle game where you control your own space ships and you kill aliens and other players. It is a lot of fun. Hope to see you in the game.
Asked by Tina A - Thu Jul 2 12:20:58 2009 - - 1 Answers - 1 Comments
A. im looking for the same thing
Answered by Kyle - Fri Jul 3 19:53:12 2009
How do you find the semi major axis of the orbit of an exoplanet?
Q. If an exoplanet orbits a star of one solar mass and the orbital period is five days, how do you fine the semi major axis of the orbit? ** I don't want the answer, I want to know how to solve the problem. I can't find out how from either of my two books ** Any help is welcomed.
Asked by , - Tue Feb 24 19:00:08 2009 - - 1 Answers - 0 Comments
A. If the star is one solar mass, then you might as well consider an object orbiting the Sun in 5 days. You can use Kepler's Third Law, which says that the square of the orbital period of a planet is proportional to the cube of it's semi-major axis. For the Sun (which also applies in this case) we can say that T = a , where T is the orbital period in years and a is the semi-major axis in Astronomical Units. Convert the period to years, then use the formula.
Answered by bikenbeer2000 - Tue Feb 24 19:23:26 2009
Q. If an exoplanet orbits a star of one solar mass and the orbital period is five days, how do you fine the semi major axis of the orbit? ** I don't want the answer, I want to know how to solve the problem. I can't find out how from either of my two books ** Any help is welcomed.
Asked by , - Tue Feb 24 19:00:08 2009 - - 1 Answers - 0 Comments
A. If the star is one solar mass, then you might as well consider an object orbiting the Sun in 5 days. You can use Kepler's Third Law, which says that the square of the orbital period of a planet is proportional to the cube of it's semi-major axis. For the Sun (which also applies in this case) we can say that T = a , where T is the orbital period in years and a is the semi-major axis in Astronomical Units. Convert the period to years, then use the formula.
Answered by bikenbeer2000 - Tue Feb 24 19:23:26 2009
What is the total energy of the electron in orbit B?
Q. In the hydrogen atom the radius of orbit B is twenty-five times greater than the radius of orbit A. The total energy of the electron in orbit A is -0.213 eV. What is the total energy of the electron in orbit B?
Asked by Mike M - Fri Dec 1 07:47:08 2006 - - 1 Answers - 0 Comments
A. the total energy of an electron in an atom inversely varies with the square of the radius of the orbit. So, if the radius of orbit B is 25 times the radius of orbit A, than the energy of an electron in orbit B will be -0.213eV/25^2 = -0.213/625 eV. (if it is 25 times greater , that means radius of orbit B is 26 times the radius of orbit A. In such case energy of an electron in orbit B will be -0.213/26^2 eV )
Answered by santosh,montfort ,L&T,kansbahal - Fri Dec 1 08:19:05 2006
Q. In the hydrogen atom the radius of orbit B is twenty-five times greater than the radius of orbit A. The total energy of the electron in orbit A is -0.213 eV. What is the total energy of the electron in orbit B?
Asked by Mike M - Fri Dec 1 07:47:08 2006 - - 1 Answers - 0 Comments
A. the total energy of an electron in an atom inversely varies with the square of the radius of the orbit. So, if the radius of orbit B is 25 times the radius of orbit A, than the energy of an electron in orbit B will be -0.213eV/25^2 = -0.213/625 eV. (if it is 25 times greater , that means radius of orbit B is 26 times the radius of orbit A. In such case energy of an electron in orbit B will be -0.213/26^2 eV )
Answered by santosh,montfort ,L&T,kansbahal - Fri Dec 1 08:19:05 2006
Will airplanes in the future go out of orbit and into space to speed up travel time?
Q. I could have sworn that I saw a commercial airlines working on this concept. Supposedly going out of orbit, you can travel anywhere in the world in 45 minutes! Please let me know if this is true or a myth. If someone has a link with details that would be even better! Cheers.
Asked by otmshank72 - Tue Jul 15 13:24:17 2008 - - 6 Answers - 1 Comments
A. its true. (only if you meant going into orbit to speed up travel time) Probably more a aerospace company working on the concept, not an airline themselves. However, it may not be exactly into orbit. The craft will be most likely suborbital. Same advantages as orbital but expends less fuel and loosens the technical requirements on the spacecraft/aircraft. many advantages, most are obvious, speed, zero air resistance, no sonic boom to disturb anyone, no weather issues etc. the question of air is easily solved. The cabin will be pressurized like airliners of today. And air can be stored in tanks or produced by certain chemical reactions. (like what NASA is using to keep their astronaust alive) however, it will take decades before this type… [cont.]
Answered by David S - Tue Jul 15 15:39:11 2008
Q. I could have sworn that I saw a commercial airlines working on this concept. Supposedly going out of orbit, you can travel anywhere in the world in 45 minutes! Please let me know if this is true or a myth. If someone has a link with details that would be even better! Cheers.
Asked by otmshank72 - Tue Jul 15 13:24:17 2008 - - 6 Answers - 1 Comments
A. its true. (only if you meant going into orbit to speed up travel time) Probably more a aerospace company working on the concept, not an airline themselves. However, it may not be exactly into orbit. The craft will be most likely suborbital. Same advantages as orbital but expends less fuel and loosens the technical requirements on the spacecraft/aircraft. many advantages, most are obvious, speed, zero air resistance, no sonic boom to disturb anyone, no weather issues etc. the question of air is easily solved. The cabin will be pressurized like airliners of today. And air can be stored in tanks or produced by certain chemical reactions. (like what NASA is using to keep their astronaust alive) however, it will take decades before this type… [cont.]
Answered by David S - Tue Jul 15 15:39:11 2008
The figure shows two planets of mass m orbiting a star of mass M. The planets are in the same orbit, with radi?
Q. The figure shows two planets of mass m orbiting a star of mass M. The planets are in the same orbit, with radius r, but are always at opposite ends of a diameter. Find an exact expression for the orbital period T.
Asked by abood07 - Fri Nov 13 02:30:10 2009 - - 2 Answers - 0 Comments
A. The force acting on one of the masses m by the other two is [GMm /R^2] + [Gmm / 4R^2] This acts as the centripetal force and hence = mR ^2 [GMm /R^2] + [Gmm / 4R^2] = mR ^2 R ^3 * ^2 = G [4 M + m] / 4 = 2 / T and hence T = 4 R ^ (3/2) / { G [4 M + m]} === ===
Answered by Pearlsawme - Fri Nov 13 03:07:18 2009
Q. The figure shows two planets of mass m orbiting a star of mass M. The planets are in the same orbit, with radius r, but are always at opposite ends of a diameter. Find an exact expression for the orbital period T.
Asked by abood07 - Fri Nov 13 02:30:10 2009 - - 2 Answers - 0 Comments
A. The force acting on one of the masses m by the other two is [GMm /R^2] + [Gmm / 4R^2] This acts as the centripetal force and hence = mR ^2 [GMm /R^2] + [Gmm / 4R^2] = mR ^2 R ^3 * ^2 = G [4 M + m] / 4 = 2 / T and hence T = 4 R ^ (3/2) / { G [4 M + m]} === ===
Answered by Pearlsawme - Fri Nov 13 03:07:18 2009
About how far does the earth travel in a yearly orbit assuming a circular orbit?
Q. Length of Earth s Orbit. The average distance from the earth to the sun is 93 million miles. About how far does the earth travel in a yearly orbit assuming a circular orbit?
Asked by sky - Thu Mar 27 16:45:44 2008 - - 1 Answers - 0 Comments
A. 2*pi*r r=93 m mi. 584.3 m miles
Answered by Kyle C - Thu Mar 27 16:50:09 2008
Q. Length of Earth s Orbit. The average distance from the earth to the sun is 93 million miles. About how far does the earth travel in a yearly orbit assuming a circular orbit?
Asked by sky - Thu Mar 27 16:45:44 2008 - - 1 Answers - 0 Comments
A. 2*pi*r r=93 m mi. 584.3 m miles
Answered by Kyle C - Thu Mar 27 16:50:09 2008
How come the "Moons" orbit is different to what it should be when circling Earth ?
Q. I have heard the Moons orbit should not be where it is when using known methods for calculating such objects positions in orbit around another object (ie. Earth). Can anybody explain this discrepancy as it has me confused ? Thanks for your assistance with this problem !
Asked by Lightbulb. - Sun Jan 7 04:42:44 2007 - - 2 Answers - 0 Comments
A. unlike most satellites of other planets,Moons orbit is near the ecliptic(the ecliptic is the path the Sun traces out along the sky) and not the Earth's equatorial plane. it is inclined abt 18.29 to 28.58 to earth equatorial plane & 5.145 to ecliptic *titan for example have only a Inclination of abt 0.35 to saturns quatorial plane and ganymede has inclination of 2.21 to the ecliptic & 0.20 to Jupiter's equator
Answered by Tharu - Sun Jan 7 07:00:58 2007
Q. I have heard the Moons orbit should not be where it is when using known methods for calculating such objects positions in orbit around another object (ie. Earth). Can anybody explain this discrepancy as it has me confused ? Thanks for your assistance with this problem !
Asked by Lightbulb. - Sun Jan 7 04:42:44 2007 - - 2 Answers - 0 Comments
A. unlike most satellites of other planets,Moons orbit is near the ecliptic(the ecliptic is the path the Sun traces out along the sky) and not the Earth's equatorial plane. it is inclined abt 18.29 to 28.58 to earth equatorial plane & 5.145 to ecliptic *titan for example have only a Inclination of abt 0.35 to saturns quatorial plane and ganymede has inclination of 2.21 to the ecliptic & 0.20 to Jupiter's equator
Answered by Tharu - Sun Jan 7 07:00:58 2007
What degrees per earth year do all the planets orbit around the sun at?
Q. I am doing a science fair project and I need to know, what degrees (0-360) around the sun does each planet orbit in one earth year? I am using it to create a program that will give me the approximate date of the next planet grouping. I have googled and searched and can't find it anywhere.
Asked by LoopStan - Wed Jan 20 19:31:54 2010 - - 1 Answers - 0 Comments
A. Read ALL of this and create a program like the one below:
Answered by Bullseye - Wed Jan 20 20:16:09 2010
Q. I am doing a science fair project and I need to know, what degrees (0-360) around the sun does each planet orbit in one earth year? I am using it to create a program that will give me the approximate date of the next planet grouping. I have googled and searched and can't find it anywhere.
Asked by LoopStan - Wed Jan 20 19:31:54 2010 - - 1 Answers - 0 Comments
A. Read ALL of this and create a program like the one below:
Answered by Bullseye - Wed Jan 20 20:16:09 2010
Why do planets that are closest to the sun orbit faster than the planets furthest away?
Q. I am helping my daughter with a science project and would like to know specifically why planets that are closest to the sun orbit faster than further planets? I am having difficulty finding a specific explaination. Serious answers only. Thank you!
Asked by Penny - Sun Feb 17 12:00:23 2008 - - 7 Answers - 0 Comments
A. There are a combination of factors. One is that gravity is stronger closer to the sun. It's strength drops off with the square of the distance away from the source, so close in gravity is a LOT stronger than farther away. Also, planets near the sun have orbits that are smaller circles than those farther away. I takes longer to go around a longer path. I could go into the technical details of how Newton's laws of motion and gravitation give rise to Kepler's laws of planetary motion but I'll stop here for now.
Answered by Steve H - Sun Feb 17 13:02:57 2008
Q. I am helping my daughter with a science project and would like to know specifically why planets that are closest to the sun orbit faster than further planets? I am having difficulty finding a specific explaination. Serious answers only. Thank you!
Asked by Penny - Sun Feb 17 12:00:23 2008 - - 7 Answers - 0 Comments
A. There are a combination of factors. One is that gravity is stronger closer to the sun. It's strength drops off with the square of the distance away from the source, so close in gravity is a LOT stronger than farther away. Also, planets near the sun have orbits that are smaller circles than those farther away. I takes longer to go around a longer path. I could go into the technical details of how Newton's laws of motion and gravitation give rise to Kepler's laws of planetary motion but I'll stop here for now.
Answered by Steve H - Sun Feb 17 13:02:57 2008
What percent of satellites orbit the earth?
Q. Compared to those that are sent out into space beyond earth's orbit. Reference? Also, not all satellites orbit the earth. They can also orbit the moon or other planets - my question is how many actually do this in relation to those that orbit the earth.
Asked by akuavi - Tue Jul 28 09:11:39 2009 - - 4 Answers - 0 Comments
A. There are hundreds of live satellites orbiting earth and thousands more dead ones but only a few around mars, at least one around the moon right now and prbably one or two other spacecraft in orbit around something in our solar system. So way less than 1%
Answered by Andy - Tue Jul 28 12:56:56 2009
Q. Compared to those that are sent out into space beyond earth's orbit. Reference? Also, not all satellites orbit the earth. They can also orbit the moon or other planets - my question is how many actually do this in relation to those that orbit the earth.
Asked by akuavi - Tue Jul 28 09:11:39 2009 - - 4 Answers - 0 Comments
A. There are hundreds of live satellites orbiting earth and thousands more dead ones but only a few around mars, at least one around the moon right now and prbably one or two other spacecraft in orbit around something in our solar system. So way less than 1%
Answered by Andy - Tue Jul 28 12:56:56 2009
If Jupiter was a black hole, would its moons maintain the same orbit?
Q. If there was a black hole where Jupiter currently is, instead of Jupiter, with the same mass as Jupiter, would the orbit of its moons be indistinguishable from how they currently are? Would the curvature of space be different if Jupiter was a black hole, causing its moons to have different orbits, or is mass all that effects the orbits, regardless of black holes having a greater curvature on space than less dense objects like planets? If the Sun was a black hole, would the planets maintain their same orbits? Wouldn't light going around Jupiter be less warped, than light going around black hole Jupiter? Would moons not be affected in the same way?
Asked by Infinity - Fri Feb 5 15:09:59 2010 - - 5 Answers - 0 Comments
A. If Jupiter were replaced by a black hole of the same mass, then the moons would remain in the same orbit, just like if the Sun was replaced by a black hole with one solar mass the orbit of the planets would not change. A Jupiter mass black hole would warp light more then the planet Jupiter right now.
Answered by zhuge_liang1 - Sat Feb 6 04:17:05 2010
Q. If there was a black hole where Jupiter currently is, instead of Jupiter, with the same mass as Jupiter, would the orbit of its moons be indistinguishable from how they currently are? Would the curvature of space be different if Jupiter was a black hole, causing its moons to have different orbits, or is mass all that effects the orbits, regardless of black holes having a greater curvature on space than less dense objects like planets? If the Sun was a black hole, would the planets maintain their same orbits? Wouldn't light going around Jupiter be less warped, than light going around black hole Jupiter? Would moons not be affected in the same way?
Asked by Infinity - Fri Feb 5 15:09:59 2010 - - 5 Answers - 0 Comments
A. If Jupiter were replaced by a black hole of the same mass, then the moons would remain in the same orbit, just like if the Sun was replaced by a black hole with one solar mass the orbit of the planets would not change. A Jupiter mass black hole would warp light more then the planet Jupiter right now.
Answered by zhuge_liang1 - Sat Feb 6 04:17:05 2010
How does intial velocity need to vary to get a circular orbit as the distance of the sun increases?
Q. Again my science teacher is a lune! We went on a website to see the simulation of the planets and gravity and I couldn't find any relationship in 30 minutes! Also I need to devise a method to predict the initial velocities needed to produce a circular orbit for any staring distance of a planet? This is 9th grade science?
Asked by LUV U PEOPLE! - Mon Oct 1 19:05:49 2007 - - 1 Answers - 0 Comments
A. Well, good luck with that.
Answered by Bill - Mon Oct 1 19:56:45 2007
Q. Again my science teacher is a lune! We went on a website to see the simulation of the planets and gravity and I couldn't find any relationship in 30 minutes! Also I need to devise a method to predict the initial velocities needed to produce a circular orbit for any staring distance of a planet? This is 9th grade science?
Asked by LUV U PEOPLE! - Mon Oct 1 19:05:49 2007 - - 1 Answers - 0 Comments
A. Well, good luck with that.
Answered by Bill - Mon Oct 1 19:56:45 2007
Can a Planet leave the Orbit of one Star and later enter Orbit around another Star?
Q. I've heard that it's been observed that planets can leave orbit around one star, "fly" through space, and later come near another star and enter its orbit. Is this true? If so, What is this phenomenon called? And where could I read about it?
Asked by supernatordjt - Wed Apr 16 11:36:32 2008 - - 8 Answers - 0 Comments
A. Its possible. Planets can be torn out of their orbits by the gravitational forces of a passing star. Galactic collisions could cause this sort of behavior. I have seen speculation that the collision with the Andromeda galaxy in 2 billion years or so could do such a thing to earth. I wouldn't bet a lot of money on that happening though. However with that said, the chances of being picked up by another star (capture is the term usually associated with the idea ) are rather low. Interstellar distances are absurdly large, and the speed of rogue planets would be rather low. Still, it is possible. For many years it was suggested that Pluto was a capture. This was before it was known that the Kuyper belt and Oort cloud harbored lots of… [cont.]
Answered by Richard R - Wed Apr 16 12:04:02 2008
Q. I've heard that it's been observed that planets can leave orbit around one star, "fly" through space, and later come near another star and enter its orbit. Is this true? If so, What is this phenomenon called? And where could I read about it?
Asked by supernatordjt - Wed Apr 16 11:36:32 2008 - - 8 Answers - 0 Comments
A. Its possible. Planets can be torn out of their orbits by the gravitational forces of a passing star. Galactic collisions could cause this sort of behavior. I have seen speculation that the collision with the Andromeda galaxy in 2 billion years or so could do such a thing to earth. I wouldn't bet a lot of money on that happening though. However with that said, the chances of being picked up by another star (capture is the term usually associated with the idea ) are rather low. Interstellar distances are absurdly large, and the speed of rogue planets would be rather low. Still, it is possible. For many years it was suggested that Pluto was a capture. This was before it was known that the Kuyper belt and Oort cloud harbored lots of… [cont.]
Answered by Richard R - Wed Apr 16 12:04:02 2008
What is the amount of work required to put a satellite in orbit?
Q. How much work must be done to lift a 1000 kg satellite into Earth orbit one earth radius above the surface? (mass of Earth=5.98x10^24kg, radius of Earth=6.38x10^6m) Please show the full solution, thanks.
Asked by freestyle67890 - Thu Apr 2 10:07:39 2009 - - 1 Answers - 0 Comments
A. You are doing work against the gravitational pull of the earth and changing the gravitational potential of the satellite. W=Ufinal - Uinitial W=-GMsMe/(Re+Re)-(-GMsMe/ Re) W=-GMsMe/Re(1/2-1) W=GMsMe/2Re where Ms-mass of satellite, Me-mass of earth, Re-radius of the earth, G-universal gravitational constant.
Answered by Denis S - Thu Apr 2 10:37:18 2009
Q. How much work must be done to lift a 1000 kg satellite into Earth orbit one earth radius above the surface? (mass of Earth=5.98x10^24kg, radius of Earth=6.38x10^6m) Please show the full solution, thanks.
Asked by freestyle67890 - Thu Apr 2 10:07:39 2009 - - 1 Answers - 0 Comments
A. You are doing work against the gravitational pull of the earth and changing the gravitational potential of the satellite. W=Ufinal - Uinitial W=-GMsMe/(Re+Re)-(-GMsMe/ Re) W=-GMsMe/Re(1/2-1) W=GMsMe/2Re where Ms-mass of satellite, Me-mass of earth, Re-radius of the earth, G-universal gravitational constant.
Answered by Denis S - Thu Apr 2 10:37:18 2009
How fast and in what direction with respect to the Earth s orbit should the rocket be fired?
Q. The orbital velocity of the Earth about the sun is 30 km/s. If the Earth were suddenly stopped in its tracks, it would simply fall radially into the Sun. Devise a plan whereby a rocket loaded with radioactive wastes could be fired into the Sun for permanent disposal. How fast and in what direction with respect to the Earth s orbit should the rocket be fired?
Asked by kevin - Thu Jul 17 19:25:40 2008 - - 1 Answers - 0 Comments
A. You could fire the rocket 30 km/s opposite Earth's motion around the sun, but you'd save a lot of fuel if you took advantage of the slingshot effect to slow the rocket as it passes the moon and again when it passes planets, including Earth several times. Whatever method you use, it will probably cost about as much energy as what you got from the material before it became waste. If that's the case, it would have been less costly to have simply left the uranium ore in the ground to begin with.
Answered by Philip J - Thu Jul 17 20:37:31 2008
Q. The orbital velocity of the Earth about the sun is 30 km/s. If the Earth were suddenly stopped in its tracks, it would simply fall radially into the Sun. Devise a plan whereby a rocket loaded with radioactive wastes could be fired into the Sun for permanent disposal. How fast and in what direction with respect to the Earth s orbit should the rocket be fired?
Asked by kevin - Thu Jul 17 19:25:40 2008 - - 1 Answers - 0 Comments
A. You could fire the rocket 30 km/s opposite Earth's motion around the sun, but you'd save a lot of fuel if you took advantage of the slingshot effect to slow the rocket as it passes the moon and again when it passes planets, including Earth several times. Whatever method you use, it will probably cost about as much energy as what you got from the material before it became waste. If that's the case, it would have been less costly to have simply left the uranium ore in the ground to begin with.
Answered by Philip J - Thu Jul 17 20:37:31 2008
How to lower the cost to orbit?
Q. If you were NASA, what would you do to lower the cost to put things into orbit? Or is it always going to be significantly expensive?
Asked by alipes_07 - Mon Dec 1 17:23:58 2008 - - 3 Answers - 0 Comments
A. Three Words: Giant F-ing Slingshot.
Answered by Ghengis - Mon Dec 1 17:31:40 2008
Q. If you were NASA, what would you do to lower the cost to put things into orbit? Or is it always going to be significantly expensive?
Asked by alipes_07 - Mon Dec 1 17:23:58 2008 - - 3 Answers - 0 Comments
A. Three Words: Giant F-ing Slingshot.
Answered by Ghengis - Mon Dec 1 17:31:40 2008
How long does it take to orbit the earth?
Q. If a satellite is traveling 8 km/s how long would it take to orbit the earth?
Asked by xelshinesterx - Sun Mar 7 03:30:10 2010 - - 3 Answers - 0 Comments
A. it would depend on the altitude of the satellite. As an example a geostationary satellite is commonly about 35,790 km altitude and takes 23hrs 56min and 4.09s to orbit. The mean radius of earth is 6,371 km. combine this with the altitude and you get a circumference of 264,905 km. which is an average speed of 3.07km/s @ 8km/s it would take this satellite about 9hrs 12min to orbit. Unless of course you are talking about 8km/s ground speed. Then it would take 1hr 23min 23.77sec
Answered by Mr X - Sun Mar 7 03:52:27 2010
Q. If a satellite is traveling 8 km/s how long would it take to orbit the earth?
Asked by xelshinesterx - Sun Mar 7 03:30:10 2010 - - 3 Answers - 0 Comments
A. it would depend on the altitude of the satellite. As an example a geostationary satellite is commonly about 35,790 km altitude and takes 23hrs 56min and 4.09s to orbit. The mean radius of earth is 6,371 km. combine this with the altitude and you get a circumference of 264,905 km. which is an average speed of 3.07km/s @ 8km/s it would take this satellite about 9hrs 12min to orbit. Unless of course you are talking about 8km/s ground speed. Then it would take 1hr 23min 23.77sec
Answered by Mr X - Sun Mar 7 03:52:27 2010
From Yahoo Answer Search: 'orbit'
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ecogeek.org
Thu, 22 Jul 2010 16:32:56 GMT+00:00
EcoGeek MacDonald Dettwiler and Associates (MDA) has a plan to develop a satellite service station to recharge and refuel already orbiting satellites. ... Investor plans rescue of abandoned orbiting satellites Business Daily Africa
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Priya Ganapati
Wed, 21 Jul 2010 19:51:16 GM
Space enthusiasts or those going through a "cool" midlife crisis can now place a miniature personal satellite into . orbit. for 5200.
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